From: Peter Zijlstra <peterz@infradead.org>
To: Zhao Forrest <forrest.zhao@gmail.com>
Cc: vatsa@linux.vnet.ibm.com, mingo@elte.hu,
containers@lists.osdl.org, linux-kernel@vger.kernel.org
Subject: Re: A question about group CFS scheduling
Date: Thu, 26 Jun 2008 10:15:12 +0200 [thread overview]
Message-ID: <1214468112.2794.9.camel@twins.programming.kicks-ass.net> (raw)
In-Reply-To: <ac8af0be0806260019q45fa7285oa0fc79fb02254d28@mail.gmail.com>
On Thu, 2008-06-26 at 15:19 +0800, Zhao Forrest wrote:
> Hi experts,
>
> In Documentation/sched-design-CFS.txt it reads:
> Group scheduler tunables:
>
> When CONFIG_FAIR_USER_SCHED is defined, a directory is created in sysfs for
> each new user and a "cpu_share" file is added in that directory.
> # cd /sys/kernel/uids
> # cat 512/cpu_share # Display user 512's CPU share
> 1024
> # echo 2048 > 512/cpu_share # Modify user 512's CPU share
> # cat 512/cpu_share # Display user 512's CPU share
> 2048
> #
> CPU bandwidth between two users are divided in the ratio of their CPU shares.
> For ex: if you would like user "root" to get twice the bandwidth of user
> "guest", then set the cpu_share for both the users such that "root"'s
> cpu_share is twice "guest"'s cpu_share.
>
> My question is: how is CPU bandwidth divided between cgroup and
> regular processes?
> For example,
> 1 the cpu_share of user "root" is set to 2048
> 2 the cpu_share of user "guest" is set to 1024
> 3 there're many processes owned by other users, which don't belong to any cgroup
A process always belongs to a (c)group.
> if the relative CPU bandwidth allocated to cgroup of "root" is 2,
> allocated to cgroup of "guest" is 1, then what's the relative CPU
> bandwidth allocated to other regular processes? 2 or 1?
Are you interested in UID based group scheduling or cgroup scheduling?
Let me explain the cgroup case (the sanest option IMHO):
initially all your tasks will belong to the root cgroup, eg:
assuming:
mkdir -p /cgroup/cpu
mount none /cgroup/cpu -t cgroup -o cpu
Then the root cgroup (cgroup:/) is /cgroup/cpu/ and all tasks will be
found in /cgroup/cpu/tasks.
You can then create new groups as sibling from this root group, eg:
cgroup:/foo
cgroup:/bar
They will get a weigth of 1024 by default, exactly as heavy as a nice 0
task.
That means that no matter how many tasks you stuff into foo, their
combined cpu time will be as much as a single tasks in cgroup:/ would
get.
This is fully recursive, so you can also create:
cgroup:/foo/bar and its tasks in turn will get as much combined cpu time
as a single task in cgroup:/foo would get.
In theory this should go on indefinitely, in practise we'll run into
serious numerical issues quite quickly.
The USER grouping basically creates a fake root and all uids (including
0) are its siblings. The only special case is that uid-0 (aka root) will
get twice the weight of the others.
next prev parent reply other threads:[~2008-06-26 8:15 UTC|newest]
Thread overview: 5+ messages / expand[flat|nested] mbox.gz Atom feed top
2008-06-26 7:19 A question about group CFS scheduling Zhao Forrest
2008-06-26 8:15 ` Peter Zijlstra [this message]
2008-06-26 8:33 ` Zhao Forrest
2008-06-26 9:43 ` Dhaval Giani
2008-06-26 11:08 ` Peter Zijlstra
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