From mboxrd@z Thu Jan 1 00:00:00 1970 Message-ID: <125483.39803.qm@domain.hid> Date: Fri, 30 Oct 2009 18:22:24 -0700 (PDT) From: Wael Showair MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="0-2142297539-1256952144=:39803" Subject: [Xenomai-core] Basic Xenomai Questions? List-Id: Xenomai life and development List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , To: Xenomai-core@domain.hid --0-2142297539-1256952144=:39803 Content-Type: text/plain; charset=us-ascii Hi All, i am beginner to Xenomai & i m trying to understand how will it go in the future so i have 2 questions: 1. the patch of Adeos just enables the sharing of hardware between different OS, (Linux Vanilla kernel & Xenomai Nucleus), does it make this step only? 2. In Xenomai 2, there r 2 different kernels Normal Linux Vanilla & Xenomai Nucleus, but i read that Xenomai 3 will tend to use PREEMPT_RT support which leads to the only one Native kernel will exist, does it mean that the Nucleus will vanish & will it be the patched RT Vanilla Linux Kernel itself? or does it mean that the Nuecleuse will no longer be a part of the kernel space so it will be in user space? I beleive in the nucleus of Xenomai must exist in all cases? Regards, Wael --0-2142297539-1256952144=:39803 Content-Type: text/html; charset=us-ascii
Hi All,
i am beginner to Xenomai & i m trying to understand how will it go in the future so i have 2 questions:

1. the patch of Adeos just enables the sharing of hardware between different OS, (Linux Vanilla kernel & Xenomai Nucleus), does it make this step only?


2. In Xenomai 2, there r 2 different kernels Normal Linux Vanilla & Xenomai Nucleus, but i read that Xenomai 3 will tend to use
 PREEMPT_RT support which leads to the only one Native kernel will exist, does it mean that the Nucleus will vanish & will it be the patched RT Vanilla Linux Kernel itself?
or does it mean that the Nuecleuse will no longer be a part of the kernel space so it will be in user space?
I beleive in the nucleus of Xenomai must exist in all cases?


Regards,
Wael

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