Re: net/smc and the RDMA core

[Bart Van Assche <Bart.VanAssche@sandisk.com>]

On Mon, 2017-05-01 at 18:33 +0200, Christoph Hellwig wrote:
> Hi Ursual, hi netdev reviewers,
> 
> how did the smc protocol manage to get merged without any review 
> on linux-rdma at all?  As the results it seems it's very substandard
> in terms of RDMA API usage, e.g. it neither uses the proper CQ API
> nor the RDMA R/W API, and other will probably find additional issues
> as well.

Hello Dave and Ursula,

It seems very rude to me to have merged the SMC protocol driver without
having involved the linux-rdma community. Anyway, I have the following
questions for Dave and Ursula:
* Since the Linux kernel is standards based: where can we find the standard
  that defines the SMC wire protocol? If this protocol has not been
  standardized yet: in what file (other than *.[ch]) in the Linux kernel
  tree has this protocol been documented?
* What are the differences between the SMC protocol, the SDP protocol and
  the rsockets protocol? How do existing implementations for these protocols
  compare to each other from a performance point of view? If no performance
  comparison between these protocols is available, shouldn't the performance
  of these protocols have been compared with each other before a review of
  the SMC driver even started?
* What are the reasons why the SDP driver was never accepted upstream? Do
  the arguments why SDP was not accepted upstream also apply to the SMC
  driver (SDP = Sockets Direct Protocol)?
* Since SMC has to be selected by specifying AF_SMC, how are users expected
  to specify whether AF_INET, AF_INET6 or yet another address family should
  be used to set up a connection between SMC
endpoints?
* Is the SMC driver limited to RoCE? Are you aware that the rsockets library
  supports multiple transport layers (RoCE, IB and iWARP)?
* Since functionality that is similar what the SMC driver provides already
  exists in user space (rsockets), why has this functionality been
  reimplemented as a kernel driver (SMC)?

Bart.