Re: explaination needed.

["Anticipating a Reply" <ruxyz@yahoo.com>]

Hi !

  On Linux , the gcc compiler produces intermediate 
assembly code in  the AT&T syntax fromat .

$ refers to the immediate value . 

Google to find more about AT&T syntax .

Cheers !

 --- Vadiraj C S <vadiraj@odysseytec.com> wrote: > 
> 
> Hello  Everyone!!
> 
> 	I was just looking at the asm code generated by
> gcc. I could not get some of the stuffs, here, I'm
> familiar with
> nasm assembler syntax, but this does not seem to be
> nasm syntax. 
> 
>  the code is for the following c program
> int main()
> {
> 	char *c ="1"
> 	c[0]= "2" ;
> }
> 
> 
> asm code for the above..
> 
>   .file   "temp.c"
>         .section        .rodata
> .LC0:
>         .string "1"
>         .text
>         .align 2
> .globl main
>         .type   main,@function
> main:
>         pushl   %ebp
>         movl    %esp, %ebp
>         subl    $8, %esp
>         andl    $-16, %esp
>         movl    $0, %eax
>         subl    %eax, %esp
>         movl    $.LC0, -4(%ebp)
>         movl    -4(%ebp), %eax
>         movb    $50, (%eax)
>         leave
>         ret
> .Lfe1:
>         .size   main,.Lfe1-main
>         .ident  "GCC: (GNU) 3.2"
> 
>   what syntax is this, and what does $ represent.
> does the .rodata mean readonly data?
> 
>  Thanks in advance..
> 
> -- 
> 	Regards
> 	Vadiraj C S
> 
> -
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