Re: scanf with pointers as arguments

[Benjamin Sobotta <mayday@gmx.net>]

Hi!

Will the problem is not the pointer but the type. Since you use short you have 
to adjust that.
That works for me:

#include<stdio.h>

int main()
{
 int i,*iptr = &i;
        short int s,*shptr = &s;
        printf("enter 2 values:\n");
        scanf("%d %hd",iptr,shptr);
        printf("%d %hd\n",*iptr,*shptr);
        printf("%d %hd\n",i,s);

 return 0;
}



On Wednesday 17 November 2004 06:50, Krishna Mohan wrote:
> Hi
> Can anybody plz tell me what's wrong with this code!
> I am getting SEGMENTATION FAULT. ofcourse, if i use &i, &s as arguments
> in scanf, it's work fine as usual. can't i use pointers which hold the
> address of i and s. plz clarify this. THANKS IN ADVANCE.
>
>  int i,*iptr = &i;
>         short s,*shptr = &s;
>         printf("enter 2 values:\n");
>         scanf("%d %d",iptr,shptr);
>         printf("%d %d\n",*iptr,*shptr);
>  printf("%d %d\n",i,s);
>
>
>
> -
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