my cpu is 860T, using bootm command boot a linux kernel image, the following message print by smc1:

bootm 300000

## Booting image at 00300000 ...
   Image Name:   Linux-2.6.20.14
   Image Type:   PowerPC Linux Kernel Image (gzip compressed)
   Data Size:    1081591 Bytes = 1 MB
   Load Address: 00100000
   Entry Point: 00100000
   Verifying Checksum ... OK
   Uncompressing Kernel Image ... OK
## Current stack ends at 0x01D5DB10 => set upper limit to 0x00800000
No initrd
## Transferring control to Linux (at address 00100000) ...

then, the program has no response.

i debug it througth BDM, in u-boot function "do_bootm_linux", execute at "kernel = (void (*)(bd_t *, ulong, ulong, ulong, ulong))hdr->ih_ep", the program branch to address "0x00000000", the code is shown as following:

00000000 mr r31,r3

00000004 mr r30,r4

00000008 mr r29,r5

0000000C mr r28,r6

00000010 mr r27,r7

00000014 bl 0x000020C8

00000018 mfmsr r0

0000001C ori r0,r0,0x30

00000020 mtspr SRR1,r0

00000024 lis r0,0xC0002004@h

00000028 ori r0,r0,0xC0002004@l

0000002C mtspr SRR0,r0

00000030 rfi

my questions are:

1. Is the code "kernel = (void (*)(bd_t *, ulong, ulong, ulong, ulong))hdr->ih_ep" branch right?

2. What's the expected code after "kernel = (void (*)(bd_t *, ulong, ulong, ulong, ulong))hdr->ih_ep"?

3. When the kernel run to the "boot/simple/head.s"?

thanks a lot

poorbeyond

2007-07-22