Re: wrong magic number (using old sources)

[selinux770@tortenboxer.de]

> Are you cross-compiling from a system with different endianness?
Don't think so. I think both systems are little endian.

I played a little bit with the sources and i found a strange error:
Actuallay, the generated magic number is correct. I checked that with an hex editor and also within the next_entry() method in private.h
the buffer, the next_entry method returns is:
buffer[0]: 8c
buffer[1]: ff
buffer[2]: 7c
buffer[3]: f9
buffer[4]: 8
buffer[5]: 0
buffer[6]: 0
buffer[7]: 0

The method returns a void pointer, that is interpreted as an uint32_t (4 bytes) pointer (*buf). Printing the first two buffer entries now, i get:
*** before conversion: buf[0] : 7cff8c
***  after conversion: buf[0] : 8c007cff
*** before conversion: buf[1] : f9000008
***  after conversion: buf[1] : 8f90000

Whereas "before conversion" shows the hex interpretation of buf[i] before le32_to_cpu(buf[i]) is called, and "after conversion" shows the value afterwards. Something wents completely wrong. It seems like a 00 is added at the beginning of buf[0]. The magic number would be correct if we would drop this 00 and take the first byte of buf[1] instead. The strange thing is that, when i declare a 
   char *tmpbuf;
and set it to
   tmpbuf=(char *)buf;
the content is correct again:
***  buf as char: tmpbuf[0] : 8c
***  buf as char: tmpbuf[1] : ff
***  buf as char: tmpbuf[2] : 7c
***  buf as char: tmpbuf[3] : f9
***  buf as char: tmpbuf[4] : 8
***  buf as char: tmpbuf[5] : 0
***  buf as char: tmpbuf[6] : 0
***  buf as char: tmpbuf[7] : 0

I don't get the problem... why is
         buf[0]     = (00) 7c ff 8c and
(char *) buf[3...0] =  f9  7c ff 8c
?

This is obviously not an error within the selinux sources, but maybe you could help me anyway?!

Thanks in advance.

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