From mboxrd@z Thu Jan 1 00:00:00 1970 Received: from [80.68.91.202] (helo=xora.org.uk) by linuxtogo.org with esmtp (Exim 4.67) (envelope-from ) id 1IT2FO-0003st-80 for openembedded-devel@lists.openembedded.org; Wed, 05 Sep 2007 23:17:14 +0200 Received: from xora.org.uk ([::ffff:85.210.12.205]) (AUTH: LOGIN dp, SSL: TLSv1/SSLv3,128bits,AES128-SHA) by xora.org.uk with esmtp; Wed, 05 Sep 2007 22:14:43 +0100 id 0006400A.46DF1C44.0000043D Date: Wed, 5 Sep 2007 22:14:37 +0100 From: Graeme Gregory To: openembedded-devel@lists.openembedded.org Message-ID: <20070905211437.GA10460@cimmeria> References: <20070904202957.GD1429@dodger.lab.datenfreihafen.org> <1189011486.7849.35.camel@localhost.localdomain> <46DEE9E3.4080206@student.utwente.nl> <1434447296.20070905205215@vanille-media.de> <1189021941.7849.46.camel@localhost.localdomain> Mime-Version: 1.0 In-Reply-To: <1189021941.7849.46.camel@localhost.localdomain> User-Agent: Mutt/1.5.13 (2006-08-11) Subject: Re: [RFC] How to handle external kernel patches in oe the right way? X-BeenThere: openembedded-devel@lists.openembedded.org X-Mailman-Version: 2.1.9 Precedence: list Reply-To: openembedded-devel@lists.openembedded.org List-Id: Using the OpenEmbedded metadata to build Distributions List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Wed, 05 Sep 2007 21:17:14 -0000 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit Content-Disposition: inline On Wed, Sep 05, 2007 at 08:52:21PM +0100, Richard Purdie wrote: > I'm afraid I'm with Mickey here. I don't like the way this "prepatching" > works and I think its pretty ugly but I can understand why people are > doing it. I'd like to see a better solution but until then what they're > doing allows them to develop effectively which is what we're supposed to > be about. > Maybe if I get some free time around october I might suggest enhancing the fetcher/patcher so that any URL can have a http://blah.com/patches.gz;patchseries=1 svn://wibble.com/branchs/smoo/;patchseries=1 And it does the right thing. Or am I going backwards? Graeme