[q] git-diff --reverse 7def2be1..7def2be1^

[Ingo Molnar <mingo@elte.hu>]

A couple of stupid Git questions (using git-1.5.4.3-2.fc8).

Sometimes i want to see the reverse diff of a particular commit.

If i want to see the normal diff i do:

   git-log -1 -p 7def2be1

But generating the reverse diff does not work:

   git-log --reverse -1 -p 7def2be1

Because the '--reverse' here is the ordering of the revlist, not the 
direction of the patch itself. And that's OK, albeit slightly 
unintuitive.

So instead i do:

   git-diff --reverse 7def2be1..7def2be1^

I've got two observations / potential suggestions:

1) the SHA1 is duplicated above, is there a way to avoid it? Initially i 
   tried the obvious extension:

      git-diff --reverse 7def2be1..^

   But Git didnt recognize that as a valid commit range.

2) is there a way to pass something like --reversediff to git-log?

   [ time passes as i read the manpage - the final thing i do when
     every other measure fails ;-) ]

   Ah, there's "git-log -R" that would achieve this. 

   The situation still feels a tiny bit inconsistent to me, and that's 
   why my attempt to figure it out intuitively based on my existing 
   practices failed:

    a) -R is not recognized by git-diff (so i cannot just standardize 
       myself on -R and have to waste neurons on remembering the 
       distinction ;-)

    b) --reverse has different meaning in git-log and git-diff.

Perhaps one solution would be if -R was recognized by git-diff as the 
meaning of --reverse is an ABI. The extension to the sha1 range 
specifier would be nice as well, it feels intuitive to me.

Hm?

	Ingo