Re: command bootu to start kernel

[Sascha Hauer <s.hauer@pengutronix.de>]

On Wed, Oct 27, 2010 at 03:33:15PM +0200, Juergen Beisert wrote:
> Belisko Marek wrote:
> > I have mini2440 board with barebox running from RAM.
> > I try to start uImage kernel for that platform but I'm little bit
> > confused how to do it.
> >
> > I do tftp uImage and the bootu uImage but it always hangs :
> >
> > commandline: console=ttySAC0,115200
> > arch_number: 1999
> >
> > I track down that theKernel pointer point to 0xffffffff (memmap return
> > (void*)-1) which is obviously wrong.
> > If I understand correctly bootu function take first parameter and try to
> > open a file and memmap. If file isn't opened successfully then convert
> > string address which is then taken for
> > theKernel pointer.
> >
> > Is this correct procedure or do I something wrong?
> 
> Try to start a zImage with "bootz". On my system 'bootm' and 'bootu' do not 
> work.

bootz is for starting zImages. At least this command has a convenient
name :)
bootz should work on your system aswell. If not, please complain loudly.
bootu is a bit tricky though. To start a raw linux image it has to be
copied to the exact address is is expected to run, for most boards this
is start of sdram + 0x8000, but this may differ on some boards (it's
basically PHYS_OFFSET + TEXT_OFFSET in the kernel)

Sascha

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