Re: [dm-crypt] recover old crypt partition

[Arno Wagner <arno@wagner.name>]

On Thu, Jan 06, 2011 at 04:33:52PM +0100, Jan Christoph Uhde wrote:
> > "sign"? Do you mean "character"? If so, 13 known, 6 unknown and
> > another 4 from 5 possibilities gives you 256^6 * 5^4  = 1.76*10^17
> > possibilities, which is a bit outside of what you can just try.
> > Anything more known about the uunknowen ones?
>
> the password is in the From:
>
> UKKKKKKKKKKKKKUUU   where U in %,#,$,_,!,^

Ah. And KK...KK is known? What are the other unknowns besides 
the Us? The Us give you 6^4 possibilities, which is about 
1300.

> > Is this plain dm-crypt?
>
> i used cryptsetup in debian sid

Yes, but did you create a LUKS partition or a plain dm-crypt one?
The default would have been dm-crypt. Hmm. That would mean the cipher 
is probably the old default of aes-cbc-plain. Can anybody confirm that
for Debian SID?

> PS: I did not receive a mail jet so please excuse that i am not replying  
> i a proper way.

You will not get one. This list is actually also for discussing
these questions. If you want to have a private discussion, you
can reach me at arno@wagner.name

Arno
-- 
Arno Wagner, Dr. sc. techn., Dipl. Inform., CISSP -- Email: arno@wagner.name 
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