From: Oleg <lego12239@yandex.ru>
To: linux-kernel@vger.kernel.org
Subject: /proc/meminfo: relations of values
Date: Fri, 22 Apr 2016 17:03:46 +0300 [thread overview]
Message-ID: <20160422140346.GA8825@localhost> (raw)
Hi, all!
Google has many explanations of what each value mean, but nothing about
relations of values (the same for Documentation/filesystems/proc.txt).
For example, i have qemu vm with x86_64 kernel:
~# dd if=/dev/zero of=tmpdata bs=$((1024*1024)) count=10; sleep 1s; \
free; cat /proc/meminfo; grep Pss: /proc/*/smaps | awk '{s+=$2} END {print s}'
total used free shared buffers cached
Mem: 509728 64172 445556 0 2696 38848
-/+ buffers/cache: 22628 487100
Swap: 0 0 0
MemTotal: 509728 kB
MemFree: 445556 kB
Buffers: 2696 kB
Cached: 38848 kB
SwapCached: 0 kB
Active: 18708 kB
Inactive: 28108 kB
Active(anon): 5284 kB
Inactive(anon): 28 kB
Active(file): 13424 kB
Inactive(file): 28080 kB
Unevictable: 0 kB
Mlocked: 0 kB
SwapTotal: 0 kB
SwapFree: 0 kB
Dirty: 32 kB
Writeback: 7640 kB
AnonPages: 5292 kB
Mapped: 4232 kB
Shmem: 40 kB
Slab: 8384 kB
SReclaimable: 3232 kB
SUnreclaim: 5152 kB
KernelStack: 424 kB
PageTables: 472 kB
NFS_Unstable: 0 kB
Bounce: 0 kB
WritebackTmp: 0 kB
CommitLimit: 254864 kB
Committed_AS: 56380 kB
VmallocTotal: 34359738367 kB
VmallocUsed: 2092 kB
VmallocChunk: 34359732272 kB
DirectMap4k: 10232 kB
DirectMap2M: 514048 kB
10070
If i understand correctly, 10070K is userspace size, but i don't know how can i
get this value from /proc/meminfo - AnonPages + ? ...
A part of 10070K are code segments; are they included in Cached value?
If not, then 22628K(used) - 100070K = 12558K - is this kernel memory?
Which values are compose it(Slab + ?...)?
The only relations i know are:
Active = Active(anon) + Active(file)
Inactive = Inactive(anon) + Inactive(file)
Slab = SReclaimable + SUnreclaim
Others are unknown. For example, i don't know how to get used value - 64172;
and why AnonPages is not equal nor Active(anon) nor Active(anon) + Inactive(anon)?
If anyone have the time for an answer, I will be grateful.
Thanks.
--
Неманов Олег (Nemanov Oleg)
reply other threads:[~2016-04-22 14:09 UTC|newest]
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