Re: [PATCH] softirq: let ksoftirqd do its job

[Jesper Dangaard Brouer <brouer@redhat.com>]

On Thu, 1 Sep 2016 14:29:25 +0200
Jesper Dangaard Brouer <brouer@redhat.com> wrote:

> On Thu, 1 Sep 2016 13:53:56 +0200
> Peter Zijlstra <peterz@infradead.org> wrote:
> 
> > On Thu, Sep 01, 2016 at 01:02:31PM +0200, Jesper Dangaard Brouer wrote:  
> > >    PID  S  %CPU     TIME+  COMMAND
> > >      3  R  50.0  29:02.23  ksoftirqd/0
> > >  10881  R  10.7   1:01.61  udp_sink
> > >  10837  R  10.0   1:05.20  udp_sink
> > >  10852  S  10.0   1:01.78  udp_sink
> > >  10862  R  10.0   1:05.19  udp_sink
> > >  10844  S   9.7   1:01.91  udp_sink
> > > 
> > > This is strange, why is ksoftirqd/0 getting 50% of the CPU time???    
> > 
> > Do you run your udp_sink thingy in a cpu-cgroup?  
> 
> That was also Paolo's feedback (IRC).  I'm not aware of it, but it
> might be some distribution (Fedora 22) default thing.

Correction, on the server-under-test, I'm actually running RHEL7.2


> How do I verify/check if I have enabled a cpu-cgroup?

Hannes says I can look in "/proc/self/cgroup"

 $ cat /proc/self/cgroup
 7:net_cls:/
 6:blkio:/
 5:devices:/
 4:perf_event:/
 3:cpu,cpuacct:/
 2:cpuset:/
 1:name=systemd:/user.slice/user-1000.slice/session-c1.scope
 
And that "/" indicate I've not enabled cgroups, right?

-- 
Best regards,
  Jesper Dangaard Brouer
  MSc.CS, Principal Kernel Engineer at Red Hat
  Author of http://www.iptv-analyzer.org
  LinkedIn: http://www.linkedin.com/in/brouer