From mboxrd@z Thu Jan 1 00:00:00 1970 Date: Fri, 21 Dec 2018 23:46:16 +0300 From: Cyrill Gorcunov Subject: Re: [PATCH 01/12] x86_64: memset_user() Message-ID: <20181221204616.GC8441@uranus> References: <20181221181423.20455-1-igor.stoppa@huawei.com> <20181221181423.20455-2-igor.stoppa@huawei.com> <20181221182515.GF10600@bombadil.infradead.org> <20181221200546.GA8441@uranus> <20181221202946.GJ10600@bombadil.infradead.org> MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Disposition: inline In-Reply-To: <20181221202946.GJ10600@bombadil.infradead.org> To: Matthew Wilcox Cc: Igor Stoppa , Andy Lutomirski , Peter Zijlstra , Dave Hansen , Mimi Zohar , Thiago Jung Bauermann , igor.stoppa@huawei.com, Nadav Amit , Kees Cook , Ahmed Soliman , linux-integrity@vger.kernel.org, kernel-hardening@lists.openwall.com, linux-mm@kvack.org, linux-kernel@vger.kernel.org List-ID: On Fri, Dec 21, 2018 at 12:29:46PM -0800, Matthew Wilcox wrote: > > > > > > That's inefficient. > > > > > > pattern = (unsigned char)c; > > > pattern |= pattern << 8; > > > pattern |= pattern << 16; > > > pattern |= pattern << 32; > > > > Won't > > > > pattern = 0x0101010101010101 * c; > > > > do the same but faster? > > Depends on your CPU. Some yes, some no. > > (Also you need to cast 'c' to unsigned char to avoid someone passing in > 0x1234 and getting 0x4646464646464634 instead of 0x3434343434343434) Cast to unsigned char is needed in any case. And as far as I remember we've been using this multiplication trick for a really long time in x86 land. I'm out of sources right now but it should be somewhere in assembly libs.