From mboxrd@z Thu Jan  1 00:00:00 1970
From: Philipp Rudo <prudo@redhat.com>
Date: Tue, 15 Feb 2022 11:27:40 +0100
Subject: Is it possible to use a stream for initrd=
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Hi Tobias,

On Wed, 9 Feb 2022 10:32:24 +0100
Tobias Powalowski <tobias.powalowski@googlemail.com> wrote:

> Sorry you misunderstood, I don't want to create the initrd.img file.
> I want to pass the zstd directly to kexec initrd= option.

sorry, that is not possible. The kexec-tools expect a file name with
--initrd. Simply passing a binary blob to be used as initrd isn't
implemented.

Thanks
Philipp

> greetings
> tpowa
> 
> Am Mi., 9. Feb. 2022 um 10:28 Uhr schrieb Baoquan He <bhe@redhat.com>:
> >
> > On 02/09/22 at 10:16am, Tobias Powalowski wrote:  
> > > Hi,
> > > I have a tmp directory with all files placed in:
> > > find . -mindepth 1 -printf '%P\0' | sort -z | LANG=C bsdtar --uid 0
> > > --gid 0 --null -cnf - -T - |\
> > >     LANG=C bsdtar --null -cf - --format=newc @- | zstd -T0 > /initrd.img
> > >
> > > and this initrd.img I want to write into kexec without creating the initrd file.
> > >
> > > kexec -l /vmlinuz-linux --initrd=/initrd.img --reuse-cmdline
> > >  systemctl kexec  
> >
> > See manpage of kexec, the EXAMPLE part:
> >
> > kexec -l /boot/vmlinux  --initrd=/boot/initrd --reuse-cmdline
> > kexec -e
> >  
> 
>