[PATCH 2/3] rcu: Describe listRCU read-side guarantees

[Frederic Weisbecker <frederic@kernel.org>]

From: "Matthew Wilcox (Oracle)" <willy@infradead.org>

More explicitly state what is, and what is not guaranteed to those
who iterate a list while protected by RCU.

[ paulmck: Apply Joel Fernandes feedback. ]

Signed-off-by: Matthew Wilcox (Oracle) <willy@infradead.org>
Reviewed-by: Joel Fernandes (Google) <joel@joelfernandes.org>
Signed-off-by: Paul E. McKenney <paulmck@kernel.org>
Signed-off-by: Frederic Weisbecker <frederic@kernel.org>
---
 Documentation/RCU/listRCU.rst | 9 +++++++++
 1 file changed, 9 insertions(+)

diff --git a/Documentation/RCU/listRCU.rst b/Documentation/RCU/listRCU.rst
index bdc4bcc5289f..ed5c9d8c9afe 100644
--- a/Documentation/RCU/listRCU.rst
+++ b/Documentation/RCU/listRCU.rst
@@ -8,6 +8,15 @@ One of the most common uses of RCU is protecting read-mostly linked lists
 that all of the required memory ordering is provided by the list macros.
 This document describes several list-based RCU use cases.
 
+When iterating a list while holding the rcu_read_lock(), writers may
+modify the list.  The reader is guaranteed to see all of the elements
+which were added to the list before they acquired the rcu_read_lock()
+and are still on the list when they drop the rcu_read_unlock().
+Elements which are added to, or removed from the list may or may not
+be seen.  If the writer calls list_replace_rcu(), the reader may see
+either the old element or the new element; they will not see both,
+nor will they see neither.
+
 
 Example 1: Read-mostly list: Deferred Destruction
 -------------------------------------------------
-- 
2.34.1