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From: Andrew Morton <akpm@linux-foundation.org>
To: Dev Jain <dev.jain@arm.com>
Cc: willy@infradead.org, linux-fsdevel@vger.kernel.org,
	linux-mm@kvack.org, linux-kernel@vger.kernel.org,
	david@redhat.com, anshuman.khandual@arm.com,
	ryan.roberts@arm.com, ziy@nvidia.com, aneesh.kumar@kernel.org
Subject: Re: [PATCH v2] xarray: Add a BUG_ON() to ensure caller is not sibling
Date: Tue, 3 Jun 2025 21:33:38 -0700	[thread overview]
Message-ID: <20250603213338.7d80bbe0e021052c20e1c5f5@linux-foundation.org> (raw)
In-Reply-To: <20250604041533.91198-1-dev.jain@arm.com>

On Wed,  4 Jun 2025 09:45:33 +0530 Dev Jain <dev.jain@arm.com> wrote:

> Suppose xas is pointing somewhere near the end of the multi-entry batch.
> Then it may happen that the computed slot already falls beyond the batch,
> thus breaking the loop due to !xa_is_sibling(), and computing the wrong
> order. For example, suppose we have a shift-6 node having an order-9
> entry => 8 - 1 = 7 siblings, so assume the slots are at offset 0 till 7 in
> this node. If xas->xa_offset is 6, then the code will compute order as
> 1 + xas->xa_node->shift = 7. Therefore, the order computation must start
> from the beginning of the multi-slot entries, that is, the non-sibling
> entry. Thus ensure that the caller is aware of this by triggering a BUG
> when the entry is a sibling entry.

Why check this thing in particular?  There are a zillion things we
could check...

> Note that this BUG_ON() is only
> active while running selftests, so there is no overhead in a running
> kernel.

hm, how do we know this?  Now and in the future?  xa_get_order() and
xas_get_order() have callers all over the place.


  reply	other threads:[~2025-06-04  4:33 UTC|newest]

Thread overview: 5+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2025-06-04  4:15 [PATCH v2] xarray: Add a BUG_ON() to ensure caller is not sibling Dev Jain
2025-06-04  4:33 ` Andrew Morton [this message]
2025-06-04  4:53   ` Dev Jain
2025-06-04 13:40 ` Zi Yan
2025-06-10  4:41 ` Dev Jain

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