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From: RAM_LOCK <Kaushik.Sarkar@netapp.com>
To: linux-c-programming@vger.kernel.org
Subject: how compiler decide the range of real numbers in C...
Date: Thu, 30 Jul 2009 10:33:25 -0700 (PDT)	[thread overview]
Message-ID: <24743191.post@talk.nabble.com> (raw)


Say 16 bit compiler (for ex Turbo C) uses 2's compliment to find the range of
signed integer.
Say for 16 bit n=16. Now applying 2's compliment equation : -2^(n-1)  to
2^(n-1) -1
so for n=16 : The range is -32768 to 32767

This is ok. The question arises when it tell about real constant's range.
For 16 bit compiler the range of real constant is : -3.4e38 to 3.4e38

How they arrived to this real constant range?

Can any one share the mathematical calculation behind it?

thnx,
RAM_LOCK


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             reply	other threads:[~2009-07-30 17:33 UTC|newest]

Thread overview: 2+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2009-07-30 17:33 RAM_LOCK [this message]
2009-07-30 17:46 ` how compiler decide the range of real numbers in C Glynn Clements

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