(v)sscanf handles %i improperly (+patch)

[Vladimir Kondratiev <vladimir.kondratiev@intel.com>]

I found (v)sscanf included in last kernels handles %i format improperly. 
Currently, up to 2.4.17, %i is handled identical to %d. However, 
accordingly to man for sscanf,

       i      Matches an  optionally  signed  integer;  the  next
              pointer  must  be a pointer to int.  The integer is
              read in base 16 if it begins with `0x' or `0X',  in
              base 8 if it begins with `0', and in base 10 other­
              wise.  Only characters that correspond to the  base
              are used.

Please, when replying, CC me: mailto:vladimir.kondratiev@intel.com

Patch is quite small (against 2.4.17):

--- vsprintf.c.orig    Thu Oct 11 20:17:22 2001
+++ vsprintf.c    Tue Dec 25 23:29:31 2001
@@ -616,8 +616,9 @@
         case 'X':
             base = 16;
             break;
-        case 'd':
         case 'i':
+            base = 0; /* autodetect */
+        case 'd':
             is_sign = 1;
         case 'u':
             break;