Re: bash arithmetic

[Jeff Largent <jlargent@imagelinks.com>]

Try it this way,

NAME=john
echo name is $NAME
echo now im gonna $NAME=$(($NAME+1))
eval ${NAME}=$(($NAME+1))
echo "john = $john"


urgrue wrote:
> simple problem:
> NAME=john
> echo name is $NAME
> echo now im gonna $NAME=$(($NAME+1))
> $NAME=$(($NAME+1))
> 
> returns:
> name is john
> now im gonna john=1
> ./testscript: john=1: command not found
> 
> but whats wrong with john=1? i want to set that variable. i can put 
> john=1 in the script (in that form) and it works fine. 
> any suggestions?
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-- 
Jeff Largent                   ImageLinks, Inc.
Sr System Admin                Melbourne, Fl 32935
(321) 253-0011                 fax: (321) 253-5559