From: Hans Reiser <reiser@namesys.com>
To: Fred -- Speed Up -- <speedup@free.fr>
Cc: reiserfs-list@namesys.com
Subject: Re: Some more questions about Reiser4 ;)
Date: Sat, 10 May 2003 22:36:49 +0400 [thread overview]
Message-ID: <3EBD46C1.9080801@namesys.com> (raw)
In-Reply-To: <000201c31721$3aca6c50$9900a8c0@xpstation>
Fred -- Speed Up -- wrote:
>
>
>
>>>When you're speaking of a graph used by the semantic layer, would it be
>>>
>>>
>part
>
>
>>>of the VFS caching process ?
>>>
>>>
>>Probably you mean dentry cache?
>>
>>
>Should be ;)
>VFS seems to be very intrusive (I mean, it does a lot of the file-handling
>process) ... doesn't it limit your initiatives in implementing new
>structures ?\
>
Yes. We manage somehow though.
>
>
>
>>>Another thing I could hardly understand : does Reiser4 keep directories
>>>apart from files so that path can be cached or are they kept with the
>>>
>>>
>same
>
>
>>>status normal files got ?
>>>
>>>
>>I can't understand you.
>>
>>
>The reason why I asked this was because I didn't knew that VFS was the one
>and only responsible for the path resolving ;)
>
That is too strong a statement. VFS delegates parts of the task to us,
particularly directory lookup.
>
>
>
>>>I didn't noticed the difference, thank you for pointing this out. I
>>>understand the "balancing" process, which is documented on your website,
>>>meaning packing dirty memory items on flushing, but I don't understand
>>>
>>>
>what
>
>
>>>you mean by "tree should not be singular" :
>>>does this mean a twig should
>>>contain more than one item ?
>>>
>>>
>>This means, that tree is as minimal height as possible. Suppose we have
>>tree of height 3. Root level (3) contains one item and 2 sevel has one
>>item. This tree is singular. That it is because, we need only two
>>levels in this case. Tree like this is possible in balancing time. Flush
>>will care about that in its time.
>>
>>
>OK, now how do you balance the tree when items are deleted, or added ? This
>operation must be very complex,
>
yes, it is.
>as you don't have enough time to rebalance
>the whole tree on every commit considering performance issues. I read tree
>balancing (I mean keeping it consistent ;)) was done periodically, you're
>saying it's done at flush time, but how can you achieve such a complex
>operation in short enough time not to affect performance ?
>
we only squeeze what is being flushed to disk. The CPU is faster than
the disk drive, so it works.
>
>
>
>>>The really interesting thing (the mysterious one :-D) is the
>>>consistency-keeping process. I didn't really understood the
>>>
>>>
>left-delimiting
>
>
>>>key concept, I guess it's something like a path in the storage tree
>>>
>>>
>>You are right :)
>>
>>
>You can't guess how happy I am ||:-D
>
>
>
>>>In a consistent tree, do all the inodes got the same left-delimiting
>>>key depth ?
>>>
>>>
>>>
>>We do not have inodes in storage tree. We have nodes instead.
>>
>>Left delimiting key means, that if node pointer item in the index part
>>of tree (levels from tree height through to 2) points to some node, then
>>node pointer item key equal to leftmost key of the node node pointer
>>points to.
>>
>>
>All right ;)
>
>
>Thank you,
>Fred
>
>
>
>
>
--
Hans
next prev parent reply other threads:[~2003-05-10 18:36 UTC|newest]
Thread overview: 11+ messages / expand[flat|nested] mbox.gz Atom feed top
2003-05-06 18:30 Some more questions about Reiser4 ;) Fred -- Speed Up --
2003-05-09 11:29 ` Yury Umanets
2003-05-10 15:32 ` Fred -- Speed Up --
2003-05-10 16:09 ` Yury Umanets
2003-05-10 17:39 ` Fred -- Speed Up --
2003-05-10 18:36 ` Hans Reiser [this message]
2003-05-10 18:57 ` Fred -- Speed Up --
2003-05-11 16:27 ` Hans Reiser
-- strict thread matches above, loose matches on Subject: below --
2003-05-08 6:23 Fred -- Speed Up --
2003-05-03 21:33 Fred -- Speed Up --
2003-05-10 18:43 ` Hans Reiser
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