Re: array size 1 ? All headers

[joy <gracecott@sancharnet.in>]

Luiz Fernando N. Capitulino wrote:

> The program:
>
> char tst[1];
> tst[0]='g';
> tst[1]='r';
>
> printf("%c %c\n", tst[0], tst[1]);
>
> compiles and works here! but to be honest, I don't why. I can prove it is
>an odd case, becase this also works (here):
>
>  
>
correct me if I'm wrong, but I feel that the code you have written is 
the classic case of a buffer overflow.
C , (I think) , does not check for array boundaries and leaves this work 
to be done by the programmer.
this is the basis of all those nasty worms running free!

> char tst[1];
> tst[0]='g';
> tst[1]='r';
> tst[2]='z';
>
> printf("%c %c %c\n", tst[0], tst[1], tst[2]);
>
>PS: GCC compiled.
>
>  
>