* Question: ioctl functions
@ 2005-04-22 22:18 Benoit Boissinot
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From: Benoit Boissinot @ 2005-04-22 22:18 UTC (permalink / raw)
To: Kernel Mailing List
It looks like (i havent checked all the tree) that every function that
is registered as ioctl (or
read_ioctl or fb_ioctl or ...) have an argument "unsigned long arg",
then each function is using
it like this:
void __user *argp = (void __user *)arg;
I am wondering why the argument isn't from type "void __user *".
Thanks,
Benoit
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2005-04-22 22:18 Question: ioctl functions Benoit Boissinot
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