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>> + struct cgroup_subsys_state *css; >> + >> + guard(rcu)(); >> + css_for_each_descendant_post(css, &cgrp->self) { >> + struct task_struct *task; >> + struct css_task_iter it; >> + >> + css_task_iter_start(css, 0, &it); >> + while ((task = css_task_iter_next(&it))) { >> + if (task->flags & PF_KTHREAD) >> + continue; >> + if (task->frozen) >> + continue; >> + >> + warn_freeze_timeout_task(cgrp, timeout, task); >> + css_task_iter_end(&it); >> + return; >> + } >> + css_task_iter_end(&it); >> + } >> + >> + buf = kmalloc(PATH_MAX, GFP_KERNEL); >> + if (!buf) >> + return; >> + >> + if (cgroup_path(cgrp, buf, PATH_MAX) < 0) >> + return; >> + >> + pr_warn("Freeze of %s took %ld sec, but no unfreezable process detected.\n", >> + buf, timeout / USEC_PER_SEC); >> +} > > This is only suitable for debugging, and, for that, this can be done from > userspace by walking the tasks and check /proc/PID/wchan. Should be > do_freezer_trap for everything frozen. If something is not, read and dump > its /proc/PID/stack. Wouldn't that work? Yes, that will do. I just hoped it might be a little bit more robust to detect it in kernel. Thanks. Note the trace printing in /proc/PID/stack is a bit less informative than show_stack(), e.g. for my test module (https://github.com/Snorch/proc-hang-module) the stack in /proc/PID/stack will be just empty. (I guess it has to do with the fact that you need less privileges to read /proc/PID/stack than dmesg, so you can do a more informative thing in dmesg. > > Thanks. > -- Best regards, Pavel Tikhomirov Senior Software Developer, Virtuozzo.