Re: [NUMA , x86_64] Why memnode_shift is chosen with the lowest possible value ?

[Eric Dumazet <dada1@cosmosbay.com>]

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Andi Kleen a écrit :
>>Using memnode_shift=33 would access only 2 bytes from this memnodemap[], 
>>touching fewer cache lines (well , one cache line). kfree() and friends 
>>would be slightly faster, at least cache friendly.
> 
> 
> Agreed. Please send a patch.

OK let's try :)

[PATCH] NUMA,x86_64 :
	Compute the highest possible value for memnode_shift,
	in order to reduce footprint of memnodemap[] to the minimum, thus
	making all users (phys_to_nid(), kfree()), more cache friendly.

Before the patch :

Node 0 MemBase 0000000000000000 Limit 00000001ffffffff
Node 1 MemBase 0000000200000000 Limit 00000003ffffffff
Using 23 for the hash shift. Max adder is 3ffffffff

After the patch :

Node 0 MemBase 0000000000000000 Limit 00000001ffffffff
Node 1 MemBase 0000000200000000 Limit 00000003ffffffff
Using 33 for the hash shift.

In this case, only 2 bytes of memnodemap[] are used, instead of 2048

Thank you

Signed-off-by: Eric Dumazet <dada1@cosmosbay.com>


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--- linux-2.6.14-rc2/arch/x86_64/mm/numa.c	2005-09-20 05:00:41.000000000 +0200
+++ linux-2.6.14-rc2-ed/arch/x86_64/mm/numa.c	2005-09-29 18:45:42.000000000 +0200
@@ -38,38 +38,62 @@
 
 int numa_off __initdata;
 
-int __init compute_hash_shift(struct node *nodes, int numnodes)
+
+/*
+ * Given a shift value, try to populate memnodemap[]
+ * Returns :
+ * 1 if OK
+ * 0 if memnodmap[] too small (of shift too small)
+ * -1 if node overlap or lost ram (shift too big)
+ */
+static int __init populate_memnodemap(
+	const struct node *nodes, int numnodes, int shift)
 {
 	int i; 
-	int shift = 20;
-	unsigned long addr,maxend=0;
-	
-	for (i = 0; i < numnodes; i++)
-		if ((nodes[i].start != nodes[i].end) && (nodes[i].end > maxend))
-				maxend = nodes[i].end;
-
-	while ((1UL << shift) <  (maxend / NODEMAPSIZE))
-		shift++;
+	int res = -1;
+	unsigned long addr, end, lost ;
 
-	printk (KERN_DEBUG"Using %d for the hash shift. Max adder is %lx \n",
-			shift,maxend);
-	memset(memnodemap,0xff,sizeof(*memnodemap) * NODEMAPSIZE);
+	memset(memnodemap, 0xff, sizeof(memnodemap));
 	for (i = 0; i < numnodes; i++) {
-		if (nodes[i].start == nodes[i].end)
+		addr = (nodes[i].start >> shift);
+		end = ((nodes[i].end + 1) >> shift);
+
+		/* check we dont loose more than 16 MB of ram */
+		lost = (nodes[i].end + 1) - (end << shift);
+		if (lost >= (1<<24))
+			return -1;
+
+		if (addr >= end)
 			continue;
-		for (addr = nodes[i].start;
-		     addr < nodes[i].end;
-		     addr += (1UL << shift)) {
-			if (memnodemap[addr >> shift] != 0xff) {
-				printk(KERN_INFO
-	"Your memory is not aligned you need to rebuild your kernel "
-	"with a bigger NODEMAPSIZE shift=%d adder=%lu\n",
-					shift,addr);
+		if (end >= NODEMAPSIZE)
+			return 0;
+		res = 1;
+		for (; addr < end; addr++) {
+			if (memnodemap[addr] != 0xff)
 				return -1;
-			} 
-			memnodemap[addr >> shift] = i;
-		} 
+			memnodemap[addr] = i;
+		}
 	} 
+	return res;
+}
+
+int __init compute_hash_shift(struct node *nodes, int numnodes)
+{
+	int shift = 20;
+
+	while (populate_memnodemap(nodes, numnodes, shift + 1) >= 0)
+		shift++;
+
+	printk(KERN_DEBUG "Using %d for the hash shift.\n",
+		shift);
+
+	if (populate_memnodemap(nodes, numnodes, shift) != 1) {
+		printk(KERN_INFO
+	"Your memory is not aligned you need to rebuild your kernel "
+	"with a bigger NODEMAPSIZE shift=%d\n",
+			shift);
+		return -1;
+	}
 	return shift;
 }