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From: Steven Scholz <steven.scholz@imc-berlin.de>
To: linux-rt-users@vger.kernel.org
Subject: appearance of /proc/interrupts ?
Date: Thu, 11 Jan 2007 10:51:28 +0100	[thread overview]
Message-ID: <45A608A0.1050407@imc-berlin.de> (raw)

Hi,

with Linux 2.6.17-rt3 /proc/interrupts looks as described on

	http://rt.wiki.kernel.org/index.php/RT_PREEMPT_HOWTO

           CPU0
  0:      11188  XT-PIC         [........N/  0]-level    pit
  1:          8  XT-PIC         [........./  0]-level    i8042
  2:          0  XT-PIC         [........N/  0]-level    cascade
  4:        131  XT-PIC         [........./ 10]-level    serial
 11:         10  XT-PIC         [........./  0]-level    eth0
 14:       4087  XT-PIC         [........./  0]-level    ide0

But when using a Linux 2.6.19.1-rt15 it looks like

           CPU0
  0:      15499   IO-APIC-edge      timer
  1:          8   IO-APIC-edge      i8042
  4:        161   IO-APIC-edge      serial
  9:          0   IO-APIC-fasteoi   acpi
 12:          3   IO-APIC-edge      i8042
 14:       4082   IO-APIC-edge      ide0
 16:         93   IO-APIC-fasteoi   eth0

which is pretty much the same as a vanilla 2.6.19.

What does it mean? Is RT PREEMPT not working correctly?

Thanks,

Steven

             reply	other threads:[~2007-01-11  9:51 UTC|newest]

Thread overview: 6+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2007-01-11  9:51 Steven Scholz [this message]
2007-01-11  9:50 ` appearance of /proc/interrupts ? Ingo Molnar
2007-01-11 11:04   ` Steven Scholz
2007-01-11 11:50     ` Robert Schwebel
2007-01-11 15:19       ` Steven Scholz
2007-01-12  9:13       ` Luotao Fu

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