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From: Arjan van de Ven <arjan@linux.intel.com>
To: Dmitry Adamushko <dmitry.adamushko@gmail.com>
Cc: Ingo Molnar <mingo@elte.hu>,
	Linux Kernel Mailing List <linux-kernel@vger.kernel.org>
Subject: Re: latencytop: optimize LT_BACKTRACEDEPTH loops a bit
Date: Sat, 02 Feb 2008 16:11:36 -0800	[thread overview]
Message-ID: <47A506B8.9030609@linux.intel.com> (raw)
In-Reply-To: <1201993171.12880.8.camel@earth>

Dmitry Adamushko wrote:
> Subject: latencytop: optimize LT_BACKTRACEDEPTH loops a bit.
> 
> It looks like there is no need to loop any longer when 'same == 0'.

thanks for the contribution!
while I like your patch, I wonder if we should go even a little further in
cleaning this up

> @@ -73,12 +73,12 @@ account_global_scheduler_latency(struct task_struct *tsk, struct latency_record
>  			continue;
>  		}
>  		for (q = 0 ; q < LT_BACKTRACEDEPTH ; q++) {
> -			if (latency_record[i].backtrace[q] !=
> -				lat->backtrace[q])
> +			unsigned long record = lat->backtrace[q];
> +
> +			if (latency_record[i].backtrace[q] != record)
>  				same = 0;
> -			if (same && lat->backtrace[q] == 0)
> -				break;
> -			if (same && lat->backtrace[q] == ULONG_MAX)
> +
> +			if (!same || record == 0 || record == ULONG_MAX)
>  				break;
>  		}

I mean, we could make it look like this:

if (latency_record[i].backtrace[q] != record) {
	same = 0;
	break;
}
/* 0 and ULONG_MAX entries denote the end of backtrace */
if (record == 0)
	break;
if (record == ULONG_MAX)
	break;


to me at least this is a bit more readable/simple than the good first step you've
already taken..
Do you want to do it this way? I'd sure encourage/endorse such a patch...

  reply	other threads:[~2008-02-03  0:13 UTC|newest]

Thread overview: 4+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2008-02-02 22:59 latencytop: optimize LT_BACKTRACEDEPTH loops a bit Dmitry Adamushko
2008-02-03  0:11 ` Arjan van de Ven [this message]
  -- strict thread matches above, loose matches on Subject: below --
2008-02-03 21:33 Dmitry Adamushko
2008-02-04  4:31 ` Arjan van de Ven

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