From mboxrd@z Thu Jan 1 00:00:00 1970 Message-ID: <48908444.3040805@csp.it> Date: Wed, 30 Jul 2008 17:09:56 +0200 From: cipollone MIME-Version: 1.0 References: <20080725111751.GA27127@hrz.tu-chemnitz.de> In-Reply-To: <20080725111751.GA27127@hrz.tu-chemnitz.de> Content-Type: text/plain; charset=ISO-8859-15; format=flowed Content-Transfer-Encoding: 7bit Subject: [B.A.T.M.A.N.] BATMAN Advanced Kernel: how much time to find a new route? Reply-To: cipollone@csp.it, The list for a Better Approach To Mobile Ad-hoc Networking List-Id: The list for a Better Approach To Mobile Ad-hoc Networking List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , To: The list for a Better Approach To Mobile Ad-hoc Networking Hi, I'm studying how BATMAN Advanced-Kernel work. I'm interesting in knowing what is the behavior of BATMAN and the reaction time of the protocol if a node exit from a range node and entered in another range node. I have discovered that (in a simulation with 3 hosts with a mobile node and 2 static node) BATMAN find a new route losing more or less 8 seconds, passing from one to the other node. But the OGMs time is 1 s and the sliding window is 64, so why it can lost 64 seconds to find another route (or 32)? So there is a equation to define a the time lost to find a new route? I have an originator interval of 1 seconds (set by default). Thank you Paolo