From: Heli <helicoterus-elih@yahoo.it>
To: Avi Kivity <avi@redhat.com>
Cc: qemu-devel@nongnu.org
Subject: Re: [Qemu-devel] How does a system call work on QEMU?
Date: Sun, 17 May 2009 10:46:13 +0200 [thread overview]
Message-ID: <4A0FCED5.6070005@yahoo.it> (raw)
In-Reply-To: <4A0C5985.6020206@redhat.com>
Avi Kivity ha scritto:
> grisu46 wrote:
>>> No. Look at target-i386/translate.c, case 0x105 for syscall
>>> emulation. Eventually it ends up calling helper_syscall().
>>>
>>
>> Simplify?
>> I am a newbie.
>
> Sorry, you're on your own. I can give you pointers but it's up to you
> to follow them. If you're serious about understanding qemu you should
> be prepared a lot of time reading the source code and processor
> documentation.
>
So it this the architecture of qemu, emulator version?
QEMU is a process that gives to o.s.guest a virtual hw
layer.
Every guest will be run by a QEMU instance.
See picture schema I prepaired: http://yfrog.com/7gqemulayersj
So system calls go from a guest application to its
operating system that communicates with its virtual
hardware. QEMU receives a system call and software emulator
QEMU performs a system call in O.S. host.
It is right?
Thanks
Chiacchiera con i tuoi amici in tempo reale!
http://it.yahoo.com/mail_it/foot/*http://it.messenger.yahoo.com
next prev parent reply other threads:[~2009-05-17 8:46 UTC|newest]
Thread overview: 15+ messages / expand[flat|nested] mbox.gz Atom feed top
2009-05-14 6:50 [Qemu-devel] How does a system call work on QEMU? helicoterus-elih
2009-05-14 10:19 ` Paul Brook
2009-05-14 13:10 ` Heli
2009-05-14 16:40 ` Avi Kivity
2009-05-14 17:11 ` grisu46
2009-05-14 17:48 ` Avi Kivity
2009-05-14 18:00 ` grisu46
2009-05-15 4:49 ` Glauber Costa
2009-05-17 8:46 ` Heli [this message]
2009-05-17 9:31 ` Avi Kivity
2009-05-17 14:41 ` Fernando Carrijo
2009-05-14 14:57 ` Mulyadi Santosa
-- strict thread matches above, loose matches on Subject: below --
2009-05-15 8:54 helicoterus-elih
2009-05-13 18:41 helicoterus-elih
2009-05-14 4:38 ` Mulyadi Santosa
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