From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: from mo-p00-ob.rzone.de (mo-p00-ob.rzone.de [81.169.146.161]) (using TLSv1 with cipher EDH-RSA-DES-CBC3-SHA (168/168 bits)) (No client certificate requested) by mail.saout.de (Postfix) with ESMTPS for ; Thu, 6 Jan 2011 16:33:56 +0100 (CET) Received: from [192.168.13.13] (f049077016.adsl.alicedsl.de [78.49.77.16]) by post.strato.de (mrclete mo63) (RZmta 24.9) with ESMTP id 205eb5n06DrnOK for ; Thu, 6 Jan 2011 16:33:55 +0100 (MET) Message-ID: <4D25E0E0.5000808@obiwahn.org> Date: Thu, 06 Jan 2011 16:33:52 +0100 From: Jan Christoph Uhde MIME-Version: 1.0 Content-Type: text/plain; charset=ISO-8859-1; format=flowed Content-Transfer-Encoding: 7bit Subject: [dm-crypt] recover old crypt partition List-Id: List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , To: dm-crypt@saout.de > "sign"? Do you mean "character"? If so, 13 known, 6 unknown and > another 4 from 5 possibilities gives you 256^6 * 5^4 = 1.76*10^17 > possibilities, which is a bit outside of what you can just try. > Anything more known about the uunknowen ones? the password is in the From: UKKKKKKKKKKKKKUUU where U in %,#,$,_,!,^ > Is this plain dm-crypt? i used cryptsetup in debian sid PS: I did not receive a mail jet so please excuse that i am not replying i a proper way. Jan