From: arvid.brodin@enea.com (Arvid Brodin)
To: kernelnewbies@lists.kernelnewbies.org
Subject: "inconsistent lock state"
Date: Thu, 27 Jan 2011 20:15:24 +0100 [thread overview]
Message-ID: <4D41C44C.20902@enea.com> (raw)
Hello,
I'm using spinlocks (spin_lock_irqsave() / spin_unlock_irqrestore()) to
protect shared resources between softirq, hardirq and non-irq kernel
contexts. When I configure PROVE_LOCKING I get
=================================
[ INFO: inconsistent lock state ]
2.6.27.54 #148
---------------------------------
inconsistent {softirq-on-W} -> {in-softirq-W} usage.
khubd/85 [HC0[0]:SC1[1]:HE0:SE0] takes:
(&priv->lock){-+..}, at: [<90152430>] schedule_ptds+0x54/0x564
{softirq-on-W} state was registered at:
[<9003856e>] trace_hardirqs_on_caller+0x92/0xc4
[<900385a8>] trace_hardirqs_on+0x8/0xc
[<90058fc2>] __slab_alloc+0xee/0x3e4
[<90059f9c>] kmem_cache_alloc+0x30/0x70
etc...
I don't understand why. Assuming that "{softirq-on-W} -> {in-softirq-W}"
means that the problem is that the lock was taken in "softirq on" (irqs
enabled) state, and at some later time in softirq context, then what is
the problem? spin_lock_irqsave() disables irqs, right? So after the lock
is taken in non-irq context, softirq cannot interrupt?
There are code paths like this:
{
spin_lock_irqsave(...);
...
spin_unlock()
...
spin_lock()
...
spin_unlock_irqrestore(...);
}
in both non-irq and softirq contexts. Could this be a problem? If I
understand correctly, spin_lock() and spin_unlock() does not touch irq
settings, so the usage above should be fine, right?
Thanks,
Arvid Brodin
Enea Services Stockholm AB
reply other threads:[~2011-01-27 19:15 UTC|newest]
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