Re: [Qemu-devel] [PATCH] [qemu-img] CPU consuming optimization

[Dmitry Konishchev <konishchev@gmail.com>]

On 18.05.2011 11:57, Stefan Hajnoczi wrote:
> Yes, optimizing is_not_zero() is good.  The only additional thing I
> suggest is adding a comment before the function to document the length
> constraint.

OK, fixed.


On 18.05.2011 12:05, Kevin Wolf wrote:
> A future bdrv_is_allocated() patch must make sure that the conversion
> falls back to a simple is_not_zero() when a backing file is used.

Thanks, I'll take this into account.


Signed-off-by: Dmitry Konishchev <konishchev@gmail.com>
---
  qemu-img.c |   30 +++++++++++++++++++++++++++---
  1 files changed, 27 insertions(+), 3 deletions(-)

diff --git a/qemu-img.c b/qemu-img.c
index e825123..7665c2f 100644
--- a/qemu-img.c
+++ b/qemu-img.c
@@ -496,14 +496,38 @@ static int img_commit(int argc, char **argv)
      return 0;
  }

+/*
+ * Checks whether the sector is not a zero sector.
+ *
+ * Attention! The len must be a multiple of 4 * sizeof(long) due to
+ * restriction of optimizations in this function.
+ */
  static int is_not_zero(const uint8_t *sector, int len)
  {
+    /*
+     * Use long as the biggest available internal data type that fits 
into the
+     * CPU register and unroll the loop to smooth out the effect of memory
+     * latency.
+     */
+
      int i;
-    len >>= 2;
-    for(i = 0;i < len; i++) {
-        if (((uint32_t *)sector)[i] != 0)
+    len /= sizeof(long);
+
+    long d0;
+    long d1;
+    long d2;
+    long d3;
+
+    for(i = 0; i < len; i += 4) {
+        d0 = ((const long*) sector)[i + 0];
+        d1 = ((const long*) sector)[i + 1];
+        d2 = ((const long*) sector)[i + 2];
+        d3 = ((const long*) sector)[i + 3];
+
+        if (d0 || d1 || d2 || d3)
              return 1;
      }
+
      return 0;
  }

-- 
1.7.4.1