Re: default menuentry matching similar entries is broken

["Vladimir 'φ-coder/phcoder' Serbinenko" <phcoder@gmail.com>]

On 03.03.2012 08:33, Seth Goldberg wrote:
> Hi,
>
>    This code in menu.c::menuentry_eq() looks wrong:
>
> {
>    const char *ptr1, *ptr2;
>    ptr1 = title;
>    ptr2 = spec;
>    while (1)
>      {
>        if (*ptr2 == '>'&&  ptr2[1] != '>'&&  *ptr1 == 0)
>          return 1;
>        if (*ptr2 == '>'&&  ptr2[1] != '>')
>          return 0;
>        if (*ptr2 == '>')
>          ptr2++;
>        if (*ptr1 != *ptr2)
>          return 0;
>        if (*ptr1 == 0)<----
>          return 1;
>        ptr1++;
>        ptr2++;
>      }
> }
>
>
>    Specifically, if there are two menuentries that differ by adding characters, this function will match the wrong one, i.e.:
Have you actually tested this? Since from the code readin just before it 
we have:

       if (*ptr1 != *ptr2)
         return 0;

So the code you point at is trigered only if both *ptr1 and *ptr2 are 0
>   Also, what's the deal with the '>' characters?  What are they supposed to do? I can't seem to find the use of'>'  documented anywhere.
It's for submenus:
"submenu>subsubmenu>entry"
>
>   Thanks,
>   --S
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>


-- 
Regards
Vladimir 'φ-coder/phcoder' Serbinenko