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Date: Thu, 12 Sep 2013 18:51:32 +0800
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Subject: Re: [Qemu-devel] Disabling IRQ error
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To: Max Filippov <jcmvbkbc@gmail.com>
Cc: qemu-ppc <qemu-ppc@nongnu.org>, qemu-devel <qemu-devel@nongnu.org>

Dear Max,
    > Does it mean an IRQ to be edge-triggered?
    No, it is a level-sensitive and active-high interrupt.
This is why i tried to use qemu_irq_raise() to trigger IRQ.


Thanks,
Simen


>> Hi Max,
>>      Thanks for your patience and help.
>>      I`ve tried to do what you said, but the problem doesn`t go away.
>> And actually i cannot add a new register to the fpga device, because the
>> fpga device i`m emulating already exists in the real world.
>> So i cannot change anything about hardware properties and linux driver for
>> this device.
>
> Then I don't get its IRQ logic. Does it mean an IRQ to be edge-triggered?
> Its model should use qemu_irq_pulse then instead of qemu_irq_raise and
> its IRQ line should be connected to edge-sensing input of interrupt controller.
> Input that you have used is also used to sense PCI IRQ and is level-sensing.
>
>>      By the way, how did you finally fix your problem?
>
> I didn't have any. (:
>