Re: what will connect the fork() with its following code ? a simple example below:

["Sat." <walking.to.remember@gmail.com>]

here is a snip in 0.11 version linux , 
in linux/init/main.c


179 if (!(pid=fork())) {
180 close(0);
181 if (open( "/etc/rc",O_RDONLY,0))
182 _exit(1);
183 execve( "/bin/sh",argv_rc,envp_rc); 
184 _exit(2);
185 }

natually, the code from 180 to 184 is runned by the new process, what
I can understand is why the new process know that the next code will
run is close(0) and why it know It will end at line 184 ?

so ,I feel that there should be some connection between  them . but
what the relationship in depth is ?

thanks your help :) 


2005/9/6, Dirk Gerdes <mail@dirk-gerdes.de>:
> There is no connection between a child an its parent.
> The child only gets a copy of the code.
> If there were a pointer to a child or to the parent, you wouldn't need any
> signals.
> The processes could communicate directly.
> 
> regards
> 
> ----- Original Message -----
> From: "Sat." <walking.to.remember@gmail.com>
> To: <linux-kernel@vger.kernel.org>
> Sent: Tuesday, September 06, 2005 11:15 AM
> Subject: what will connect the fork() with its following code ? a simple
> example below:
> 
> 
> > if(!(pid=fork())){
> >     ......
> >     printk("in child process");
> >     ......
> > }else{
> >     .....
> >     printk("in father process");
> >     .....
> > }
> >
> > this is a classical example, when the fork() system call runs, it will
> > build a new process and active it . while the schedule() select the
> > new process it will run. this is rather normal.
> >
> > but there is always a confusion in my minds.
> > because , sys_fork() only copies father process and configure some new
> > values., and do nothing . so the bridge  between the new process and
> > its following code, printk("in child process"), seems disappear . so I
> > always believe that the new process should have a pointer which point
> > the code "printk("in child process");". except this , there are not
> > any connection between them ?
> >
> > very confused :(
> >
> > any help will  appreciate  !
> >
> >
> >
> > --
> > Sat.
> > -
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> 
> 


-- 
Sat.