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From: David Howells <dhowells-H+wXaHxf7aLQT0dZR+AlfA@public.gmane.org>
To: "Serge E. Hallyn" <serue-r/Jw6+rmf7HQT0dZR+AlfA@public.gmane.org>
Cc: dhowells-H+wXaHxf7aLQT0dZR+AlfA@public.gmane.org,
	containers-cunTk1MwBs9QetFLy7KEm3xJsTq8ys+cHZ5vskTnxNA@public.gmane.org,
	akpm-de/tnXTf+JLsfHDXvbKv3WD2FQJk+8+b@public.gmane.org
Subject: Re: Containers don't handle keys, but should they?
Date: Fri, 14 Mar 2008 15:49:20 +0000	[thread overview]
Message-ID: <8853.1205509760@redhat.com> (raw)
In-Reply-To: <20080314145447.GG9741-6s5zFf/epYLPQpwDFJZrxKsjOiXwFzmk@public.gmane.org>

Serge E. Hallyn <serue-r/Jw6+rmf7HQT0dZR+AlfA@public.gmane.org> wrote:

> It looks like maybe just adding a struct user_namespace * to a struct key
> should suffice.

That's not quite sufficient.  The per-UID key_user structs also need to be
differentiated.  Unfortunately, I can't just merge it into user_struct as I
then end up with a reference loop user_struct -> uid_keyring -> user_struct.

Rooting the key_user trees in user_namespace will probably do the trick.

A couple of questions:

 (1) A process may inherit a session keyring over clone().  Should this be
     discarded if CLONE_NEWUSER is set?  Or would I need to copy it?

 (2) In a recent patch, I've given the root user its own quota limits.  Is UID
     0 always the root user in any container?  Or would it make more sense
     just to scrap the per-root quota limits?

David

  parent reply	other threads:[~2008-03-14 15:49 UTC|newest]

Thread overview: 5+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2008-03-14 11:37 Containers don't handle keys, but should they? David Howells
     [not found] ` <7519.1205494679-H+wXaHxf7aLQT0dZR+AlfA@public.gmane.org>
2008-03-14 11:44   ` Kirill Korotaev
2008-03-14 14:54   ` Serge E. Hallyn
     [not found] ` <20080314145447.GG9741-6s5zFf/epYLPQpwDFJZrxKsjOiXwFzmk@public.gmane.org>
2008-03-14 15:49   ` David Howells [this message]
     [not found]     ` <8853.1205509760-H+wXaHxf7aLQT0dZR+AlfA@public.gmane.org>
2008-03-14 16:17       ` Serge E. Hallyn

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