Re: [PATCH V5 2/3] PCI: Create device tree node for selected devices

[clement.leger@bootlin.com]

Le 2023-01-03 19:44, Lizhi Hou a écrit :
> On 1/2/23 05:56, Clément Léger wrote:
>> Le Thu, 15 Dec 2022 09:30:45 -0800,
>> Lizhi Hou <lizhi.hou@amd.com> a écrit :
>> 
>>> +};
>>> +
>>> +static int of_pci_prop_device_type(struct pci_dev *pdev,
>>> +				   struct of_changeset *ocs,
>>> +				   struct device_node *np)
>>> +{
>>> +	return of_changeset_add_prop_string(ocs, np, "device_type", "pci");
>>> +}
>>> +
>>> +static int of_pci_prop_address_cells(struct pci_dev *pdev,
>>> +				     struct of_changeset *ocs,
>>> +				     struct device_node *np)
>>> +{
>>> +	return of_changeset_add_prop_u32(ocs, np, "#address_cells",
>>> +					 OF_PCI_ADDRESS_CELLS);
>>> +}
>>> +
>>> +static int of_pci_prop_size_cells(struct pci_dev *pdev,
>>> +				  struct of_changeset *ocs,
>>> +				  struct device_node *np)
>>> +{
>>> +	return of_changeset_add_prop_u32(ocs, np, "#size_cells",
>>> +					 OF_PCI_SIZE_CELLS);
>>> +}
>> Hi Lizhi,
>> 
>> For all these functions, the "pdev" parameter is actually unused.
>> 
>> [snip]
> Ok. I will remove unused pdev.
>> 
>>> +
>>> +static int of_pci_prop_compatible(struct pci_dev *pdev,
>>> +				  struct of_changeset *ocs,
>>> +				  struct device_node *np)
>>> +{
>>> +	const char *compat_strs[PROP_COMPAT_NUM] = { 0 };
>>> +	int i, ret;
>>> +
>>> +	compat_strs[PROP_COMPAT_PCI_VVVV_DDDD] =
>>> +		kasprintf(GFP_KERNEL, "pci%x,%x", pdev->vendor, pdev->device);
>> Maybe it should be better to use "pci%04x,%04x" to keep the existing
>> naming.
> 
> Based on
> https://www.devicetree.org/open-firmware/bindings/pci/pci2_1.pdf,
> "pci%x,%x" should be used?
> 
> "name" Based on the PCI Class Code register, pick a name from Table 1.
> If none apply, generate a name of the
> form pciVVVV,DDDD as described below under "compatible".
> 
> VVVV, DDDD, SSSS, ssss and RR are lower-case ASCII hexadecimal numbers
> without leading zeroes.

You might be right then ! I just looked at the already existing 
device-tree
which adds leading zeroes. Someone like Rob or Frank might be able to 
answer
on that.

Clément

> 
> 
> Thanks,
> 
> Lizhi
> 
>>