From: _z33 <timid.Gentoo@gmail.com>
To: linux-c-programming@vger.kernel.org
Subject: Re: typecasting - explain
Date: Fri, 09 Sep 2005 15:52:08 +0530 [thread overview]
Message-ID: <dfrnos$tnv$1@sea.gmane.org> (raw)
In-Reply-To: <6a00c8d505090902462df47aa4@mail.gmail.com>
Steve Graegert wrote:
>
> char *s;
> int *i;
>
> s = (int *)malloc(128 * sizeof(char));
> i = (char *)malloc(128 * sizeof(int));
>
> s = "malloc is cool!";
> printf("s: %s\n", s);
> printf("s: %d\n", s);
>
> i = "malloc is cool!";
> printf("i: %s\n", i);
> printf("i: %d\n", i);
>
> This piece of code prints:
>
> s: malloc is cool!
> s: 4350328
> i: malloc is cool!
> i: 4350328
>
The illustration was too simple and good, for me to understand.
Thanks :)
> You see, casting changes the interpretation of bits when they are
> read. The assigment of a particular type to a variable of another
> type destroys the original type information (i.e. loss of precision).
>
destroys the original type information? Couldn't understand this part.
You are still able to recover the string, regardless of what kind of
datatype you store in. The only disadvantage I that, this obscures the
logic of the program.
> Yes function pointers are legal. ANSI C99 says:
>
> "J.5.7 Function pointer casts
> 1 A pointer to an object or to void may be cast to a pointer to a
> function, allowing data to be invoked as a function (6.5.4).
> 2 A pointer to a function may be cast to a pointer to an object or to
> void, allowing a
> function to be inspected or modified (for example, by a debugger) (6.5.4)."
>
> A function name is just a pointer to the memory location where the
> function is found at runtime. It can be queried, modified and cast to
> other types. It behaves like a variable. Take a look at the
> sigaction structure:
>
> struct sigaction {
> /* SIG_DFL, SIG_IGN or pointer to function */
> void (*sa_handler)(int);
> ... /* some other fields */
> };
>
> You can define sigaction as follows:
>
> void handler(int signo) {
> doneflag = 1;
> }
>
> struct sigaction sa;
> sa.sa_handler = handler;
> ...
>
> Here, sa_handler is registered as a function to be called when the
> specified signal occurrs.
>
> Just handle function pointers as simple pointer variables.
Have still one silly question ---
since you say function pointers are similar to simple pointer
variables, and that's why the typecast works, what would the following
code mean?
void handler1 (int a) {
/* body of handler - 1 */
printf ("HANDLER - 1 \n");
}
void handler2 (int a) {
/* body of handler - 2 */
printf ("HANDLER - 2 \n");
}
struct sigaction sa;
sa.sa_handler = (handler2 *) handler1;
Is this possible? if so, what does it mean?
_z33
--
I love TUX; well... that's an understatement :)
next prev parent reply other threads:[~2005-09-09 10:22 UTC|newest]
Thread overview: 12+ messages / expand[flat|nested] mbox.gz Atom feed top
2005-09-09 19:46 typecasting - explain _z33
2005-09-09 7:33 ` kaushal
2005-09-09 8:48 ` _z33
2005-09-09 9:28 ` Jarmo
2005-09-09 10:04 ` _z33
2005-09-09 13:19 ` Glynn Clements
2005-09-09 9:46 ` Steve Graegert
2005-09-09 10:22 ` _z33 [this message]
2005-09-09 10:49 ` Steve Graegert
2005-09-09 11:10 ` _z33
2005-09-09 11:29 ` Steve Graegert
2005-09-09 13:17 ` Glynn Clements
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