[LARTC] Re: Not understanding network setup!!

[LARTC] Re: Not understanding network setup!!

[Jarek Poplawski]

Eliot, Wireless and Server Administrator, Great Lakes Internet wrote:
> -----Original Message-----
> From: lartc-bounces@mailman.ds9a.nl
> [mailto:lartc-bounces@mailman.ds9a.nl] On Behalf Of
> ramsurrunv@mx.uom.ac.mu
> Sent: Thursday, June 01, 2006 2:58 PM
> To: lartc@mailman.ds9a.nl
> Subject: [LARTC] Not understanding network setup!! 
> 
>> Hi to all,
...
> First, 10.0.0.0/31 would be a network address. Second, a 31 bit subnet
> is meaningless. It only offers two addresses, the network address at
> 10.0.0.0 and the broadcast address at 10.0.0.1. That leaves no available
> addresses for host addresses. You probably mean /30 instead of /31. If
> you were using a /30, then you would run:
> 
> ip addr add 10.0.0.1/30 dev eth1
> ip addr add 10.0.0.5/30 dev eth2
> ip addr add 10.0.0.9/30 dev teql0
> 
> The .1, .5, and .9 would be the first available addresses in their
> respective subnets.

You probably mean /28 instead of /30:

ip addr add 10.0.0.9/28 dev teql0

Jarek P.

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Re: [LARTC] Re: Not understanding network setup!!

[Jarek Poplawski]

Eliot, Wireless and Server Administrator, Great Lakes Internet wrote:
>> -----Original Message-----
>> From: Jarek Poplawski [mailto:jarkap@poczta.onet.pl]
>> Sent: Friday, June 02, 2006 9:57 AM
>> To: Eliot, Wireless and Server Administrator, Great Lakes Internet
>> Cc: lartc@mailman.ds9a.nl
>> Subject: Re: [LARTC] Re: Not understanding network setup!!
>>
...

>> Maybe we are thinking about something else but I don't think:
>> "If you were using a /30, then" ... ".5, and .9 would be the
>> first available addresses in their respective subnets" is all
>> correct.
> 
> 10.0.0.0/30:
> 
> 10.0.0.0 - NETWORK ADDRESS
> 10.0.0.1 - HOST
> 10.0.0.2 - HOST
> 10.0.0.3 - BROADCAST ADDRESS
> 
> First available address is .1
> 
> 10.0.0.4/30:
> 
> 10.0.0.4 - NETWORK ADDRESS
> 10.0.0.5 - HOST
> 10.0.0.6 - HOST
> 10.0.0.7 - BROADCAST ADDRESS
> 
> First available address is .5
> 
> 10.0.0.8/30:
> 
> 10.0.0.8  - NETWORK ADDRESS
> 10.0.0.9  - HOST
> 10.0.0.10 - HOST
> 10.0.0.11 - BROADCAST ADDRESS
> 
> First available address is .9
> 
> Thus:
> 
> "The .1, .5, and .9 would be the first available addresses in their
> respective subnets."
> 
> Is a true statement. 
> 
> How are you interpreting this?


OH! Now I understand! I'm sorry for bothering you and many thanks 
for this clare explaining.

Jarek P.
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