From mboxrd@z Thu Jan 1 00:00:00 1970 Received: from mailman by lists.gnu.org with tmda-scanned (Exim 4.43) id 1EZmY5-0006hF-RS for qemu-devel@nongnu.org; Wed, 09 Nov 2005 04:47:22 -0500 Received: from exim by lists.gnu.org with spam-scanned (Exim 4.43) id 1EZmXy-0006gh-J6 for qemu-devel@nongnu.org; Wed, 09 Nov 2005 04:47:17 -0500 Received: from [199.232.76.173] (helo=monty-python.gnu.org) by lists.gnu.org with esmtp (Exim 4.43) id 1EZmR7-0006Mh-8l for qemu-devel@nongnu.org; Wed, 09 Nov 2005 04:40:10 -0500 Received: from [64.233.162.195] (helo=zproxy.gmail.com) by monty-python.gnu.org with esmtp (Exim 4.34) id 1EZmR6-0001VO-HZ for qemu-devel@nongnu.org; Wed, 09 Nov 2005 04:40:08 -0500 Received: by zproxy.gmail.com with SMTP id i28so100524nzi for ; Wed, 09 Nov 2005 01:40:03 -0800 (PST) Message-ID: Date: Wed, 9 Nov 2005 17:40:03 +0800 From: zheng sw MIME-Version: 1.0 Content-Type: text/plain; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable Content-Disposition: inline Subject: [Qemu-devel] Login a guest use commandline Reply-To: qemu-devel@nongnu.org List-Id: qemu-devel.nongnu.org List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , To: qemu-devel@nongnu.org when I run the command in bash: "sudo qemu -hda testaa.img -boot c -localtime -serial stdio -pidfile pidfile1.txt && sleep 300 && root && 123456 && ifconfig" root is the guest's user, 123456 is password, Why can't I login in the guest and run the ifconfig? and run "sudo qemu -hda testaa.img -boot c -localtime -serial stdio -pidfile pidfile1.txt && root && 123456 && ifconfig" is same Is the command like "ssh"? Thank you!