From: Ard van Breemen <ard@telegraafnet.nl>
To: lartc@vger.kernel.org
Subject: Re: [LARTC] help on iproute2
Date: Tue, 05 Mar 2002 17:36:50 +0000 [thread overview]
Message-ID: <marc-lartc-101534985520015@msgid-missing> (raw)
In-Reply-To: <marc-lartc-101506260304664@msgid-missing>
On Sat, Mar 02, 2002 at 01:48:43AM -0800, Bambang Yulianto wrote:
> hi guys .. I'm linux newbie
> I have LAN that connected to internet.
> here is the pic :
>
> [internet]----------[Linux]----------[LAN]
> | | |
> 202.149.83.192-207 202.149.83.194 192.168.0.1-35
>
> with RedHat Linux 2.4.18, how can I make every 4 ip on
> LAN will be 1 ip on the internet ? (sorry abt my
> english )
> example:
>
> 192.168.0.1-4 ---> 202.149.83.195
> 192.168.0.4/30 --> 202.149.83.196
> 192.168.0.8/30 --> 202.149.83.197
You are actually saying that your system was masquerading.
> with my old linux (2.2.16) ..
> I use :
> modprobe dummy
> ifconfig dummy0 202.149.83.195 netmask 255.255.255.240
> ifconfig dummy0:1 202.149.83.196 netmask
> 255.255.255.240
> ifconfig dummy0:2 202.149.83.197 netmask
> 225.255.255.240
> .
> .
> .
> ip rule add from 192.168.0.0/30 nat 202.149.83.195
> ip rule add from 192.168.0.4/30 nat 202.149.83.196
> ip rule add from 192.168.0.8/30 nat 202.149.83.197
> .
> .
> .
>
> but It's NOT WORKING on my new 2.4.18 Linux.
This is on 2.2 a way to masquerade from specific ip adresses.
As you can read in the ip manual, it really uses the ipchains masquarading
stuff.
As it also says in the manual that this has completely been removed
(except for fastnat) from that layer, since netfilter does it good.
> what should I do ?
Use netfilter/iptables.
iptables -t nat --append POSTROUTING --source 192.168.0.0/30 --jump SNAT --to-source 202.149.83.195
Or something like that.
--
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prev parent reply other threads:[~2002-03-05 17:36 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2002-03-02 9:48 [LARTC] help on iproute2 Bambang Yulianto
2002-03-02 13:24 ` bert hubert
2002-03-02 13:45 ` Julian Anastasov
2002-03-05 17:36 ` Ard van Breemen [this message]
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