From: Yaron Benita <ybenita@yahoo.com>
To: lartc@vger.kernel.org
Subject: Re: [LARTC] How to be decided default burst , cburst value ?
Date: Mon, 19 May 2003 06:14:59 +0000 [thread overview]
Message-ID: <marc-lartc-105332501113710@msgid-missing> (raw)
In-Reply-To: <marc-lartc-105331428108242@msgid-missing>
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You should use the following formula. I did some
tests and it works.
for rate 30Mbit/s use burst/cburst = 18k.
Use that as a starting point. For other rate just
calculate the ratio and it hould give you the most
accurate values.
Example: Rate 15Mbit/s use 9k ( 30/15 = 2 --> 18/2
= 9).
All the best.
--- openings <openings@palgong.knu.ac.kr> wrote:
> Hi.
>
> I know that quantum value is decided by rate/r2q.
>
> but, I don't know how to be decided burst, cburst
> value.
>
> How to be decided default burst and cburst value?
>
> ,\x04S
>
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next prev parent reply other threads:[~2003-05-19 6:14 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2003-05-19 3:16 [LARTC] How to be decided default burst , cburst value ? openings
2003-05-19 6:14 ` Yaron Benita [this message]
2003-05-19 8:44 ` Stef Coene
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