From: "???????? ?????" <skekes@pylones.gr>
To: lartc@vger.kernel.org
Subject: Re: [LARTC] HTB burstable for 2 interface , how ?
Date: Thu, 03 Jul 2003 09:12:57 +0000 [thread overview]
Message-ID: <marc-lartc-105722381102941@msgid-missing> (raw)
In-Reply-To: <marc-lartc-105722285902235@msgid-missing>
Well this can be done easily
You have to define a class having rate and ceiling 1024 kbps ( Kilobytes
if you want kilobits make its kbits ) in order not to exceed this limit.
Then you have to create two subclasses for the two networks by having as
rate 512 and ceiling 1024. Then you must make the apropriate filters
that will classify the traffic in the right flows.
All theese for eth0.
So when the 192.168.1.0 is idle 192.168.2.0 will allocate all the 1024
kbps bandwidth but when both will have traffic then they will take 512 each.
rio@martin.mu wrote:
>Dear folks,
>Here goes my bandwidth manager:
>
>INTERNET
>|
>|eth0 202.14.41.1
>BW.Manager
>| |
>| +----eth1----192.168.1.0/24
>|
>+------eth2----192.168.2.0/24
>
>Total incoming bandwidth to eth0 is 1024kbps
>should be shared to eth1 and eth2, which mean each get 512Kbps and
>burstable to 1024Kbps if other host is idle.
>
>My question is how do i apply HTB to these situation ?
>As far as i know eth1 and eth2 should be define as parent and cannot be as
>children.
>
>Regards,
>Rio Martin.
>
>
>
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next prev parent reply other threads:[~2003-07-03 9:12 UTC|newest]
Thread overview: 10+ messages / expand[flat|nested] mbox.gz Atom feed top
2003-07-03 8:56 [LARTC] HTB burstable for 2 interface , how ? rio
2003-07-03 9:12 ` Stef Coene
2003-07-03 9:12 ` ???????? ????? [this message]
2003-07-03 9:18 ` Martin Devera
2003-07-03 9:38 ` rio
2003-07-03 9:50 ` Stef Coene
2003-07-03 11:45 ` Joel
2003-07-04 16:39 ` Don Cohen
2003-07-07 3:54 ` Leonardo Balliache
2003-07-09 3:22 ` Leonardo Balliache
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