From: Stef Coene <stef.coene@docum.org>
To: lartc@vger.kernel.org
Subject: Re: [LARTC] tc -s -d explanation
Date: Thu, 11 Sep 2003 17:10:33 +0000 [thread overview]
Message-ID: <marc-lartc-106330047911566@msgid-missing> (raw)
In-Reply-To: <marc-lartc-106327715915946@msgid-missing>
On Thursday 11 September 2003 12:44, Damjan wrote:
> I want to understand the output of the "tc -s -d ..." command.
> Can someone explain in detail what this means:
>
> class htb 1:100 parent 1:10 prio 0 quantum 1000 rate 40Kbit ceil 40Kbit
> burst 1000Kb/8 mpu 0b cburst 1000Kb/8 mpu 0b level 0
> Sent 3733691 bytes 2658 pkts (dropped 0, overlimits 0)
> rate 48525bps 34pps
> lended: 2658 borrowed: 0 giants: 0
> tokens: -59999999 ctokens: -59999999
>
>
>
> I want to know what is:
> quantum 1000
> burst 1000Kb/8 (whats the /8)
> mpu 0b
> level 0
> tokens: -59999999 ctokens: -59999999 (what does this mean?)
I have some more info on the faq page on docum.org.
But the -59999999 is very strange. Can you post all your tc commands? And
also check out your kernel log files for errors.
Stef
--
stef.coene@docum.org
"Using Linux as bandwidth manager"
http://www.docum.org/
#lartc @ irc.oftc.net
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next prev parent reply other threads:[~2003-09-11 17:10 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2003-09-11 10:44 [LARTC] tc -s -d explanation Damjan
2003-09-11 17:10 ` Stef Coene [this message]
2003-09-11 19:09 ` Damjan
2003-09-12 17:00 ` Stef Coene
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