Re: List all commits of a specified file in oldest to newest order

[Junio C Hamano <gitster@pobox.com>]

Jeff King <peff@peff.net> writes:

> As a workaround, you can get what you want by two separate traversals:
> one to collect the commits via --follow, and then another to actually
> show them (but without doing any further walking). Like:
>
>   git log --follow --format=%H -- $your_file |
>   git log --stdin --no-walk --reverse [--oneline, -p, etc]

We learn new things every day.

Knowing the implementation, it is sort of obvious (we push the
objects into the pending list, populate the revs.commits in
prepare_revision_walk() from the pending list in order,
get_revision() first reverses the revs.commits and then gives out
the elements), but I didn't know the combination of "--no-walk" and
"--reverse" did something sensible ;-)

Thanks.