On Monday 21 March 2011 23:40:57 hlabishi kobo wrote:
[...]
> I actually printed the seq_bits[i] and that is basically why i used 32
> but that was just for debugging purpose. But actually if i use
> NUM_WORDS, my weighted sum become very small whereas if i use 32 it
> becomes very big, trying to understand what might be causing it to be
> that way.

NUM_WORDS == amount of unsigned long/words
WORD_BIT_SIZE == amount of bits in a unsigned long
TQ_LOCAL_WINDOW_SIZE == sum of bits in seq_bits

Nothing really fancy here.

> > you only calculate the weighted sum of a single "word" (which you static
> > casted to int....?) and not all words.
> 
> i actually dont understand this very well, how many words does seq_bits[i]
> have?

a single "word"/unsigned long. seq_bits consist of NUM_WORDS words (words are 
defined in context of seq_bits as unsigned long - that's why we removed 
TYPE_OF_WORD completely and just use unsigned long).

Regards,
	Sven