Re: [v5 4/4] mm, oom, docs: describe the cgroup-aware OOM killer

Roman Gushchin
2017-08-16T14:43:44Z

On Tue, Aug 15, 2017 at 01:56:24PM -0700, David Rientjes wrote:
> On Tue, 15 Aug 2017, Roman Gushchin wrote:
>
> > > > diff --git a/Documentation/cgroup-v2.txt b/Documentation/cgroup-v2.txt
> > > > index dec5afdaa36d..22108f31e09d 100644
> > > > --- a/Documentation/cgroup-v2.txt
> > > > +++ b/Documentation/cgroup-v2.txt
> > > > @@ -48,6 +48,7 @@ v1 is available under Documentation/cgroup-v1/.
> > > > 5-2-1. Memory Interface Files
> > > > 5-2-2. Usage Guidelines
> > > > 5-2-3. Memory Ownership
> > > > + 5-2-4. Cgroup-aware OOM Killer
> > >
> > > Random curiousness, why cgroup-aware oom killer and not memcg-aware oom
> > > killer?
> >
> > I don't think we use the term "memcg" somewhere in v2 docs.
> > Do you think that "Memory cgroup-aware OOM killer" is better?
> >
>
> I think it would be better to not describe it as its own entity, but
> rather a part of how the memory cgroup works, so simply describing it in
> section 5-2, perhaps as its own subsection, as how the oom killer works
> when using the memory cgroup is sufficient. I wouldn't separate it out as
> a distinct cgroup feature in the documentation.

Ok I've got the idea, let me look, what I can do.
I'll post an updated version soon.

>
> > > > + cgroups. The default is "0".
> > > > +
> > > > + Defines whether the OOM killer should treat the cgroup
> > > > + as a single entity during the victim selection.
> > >
> > > Isn't this true independent of the memory.oom_kill_all_tasks setting?
> > > The cgroup aware oom killer will consider memcg's as logical units when
> > > deciding what to kill with or without memory.oom_kill_all_tasks, right?
> > >
> > > I think you cover this fact in the cgroup aware oom killer section below
> > > so this might result in confusion if described alongside a setting of
> > > memory.oom_kill_all_tasks.
> > >
>
> I assume this is fixed so that it's documented that memory cgroups are
> considered logical units by the oom killer and that
> memory.oom_kill_all_tasks is separate? The former defines the policy on
> how a memory cgroup is targeted and the latter defines the mechanism it
> uses to free memory.

Yes, I've fixed this. Thanks!

> > > > +Cgroup-aware OOM Killer
> > > > +~~~~~~~~~~~~~~~~~~~~~~~
> > > > +
> > > > +Cgroup v2 memory controller implements a cgroup-aware OOM killer.
> > > > +It means that it treats memory cgroups as first class OOM entities.
> > > > +
> > > > +Under OOM conditions the memory controller tries to make the best
> > > > +choise of a victim, hierarchically looking for the largest memory
> > > > +consumer. By default, it will look for the biggest task in the
> > > > +biggest leaf cgroup.
> > > > +
> > > > +Be default, all cgroups have oom_priority 0, and OOM killer will
> > > > +chose the largest cgroup recursively on each level. For non-root
> > > > +cgroups it's possible to change the oom_priority, and it will cause
> > > > +the OOM killer to look athe the priority value first, and compare
> > > > +sizes only of cgroups with equal priority.
> > >
> > > Maybe some description of "largest" would be helpful here? I think you
> > > could briefly describe what is accounted for in the decisionmaking.
> >
> > I'm afraid that it's too implementation-defined to be described.
> > Do you have an idea, how to describe it without going too much into details?
> >
>
> The point is that "largest cgroup" is ambiguous here: largest in what
> sense? The cgroup with the largest number of processes attached? Using
> the largest amount of memory?
>
> I think the documentation should clearly define that the oom killer
> selects the memory cgroup that has the most memory managed at each level.

No problems, I'll add a clarification.

Thank you!