From mboxrd@z Thu Jan 1 00:00:00 1970 From: Lon Hohberger Date: Tue, 09 Oct 2012 13:13:38 -0400 Subject: [Cluster-devel] fence daemon problems In-Reply-To: <20121003164433.GD12614@redhat.com> References: <24E144B8C0207547AD09C467A8259F755768AE73@lisa.maurer-it.com> <24E144B8C0207547AD09C467A8259F755769CF56@lisa.maurer-it.com> <20121003144614.GB12614@redhat.com> <24E144B8C0207547AD09C467A8259F75576A155B@lisa.maurer-it.com> <20121003162411.GC12614@redhat.com> <24E144B8C0207547AD09C467A8259F75576A15CB@lisa.maurer-it.com> <20121003164433.GD12614@redhat.com> Message-ID: <50745B42.8070900@redhat.com> List-Id: To: cluster-devel.redhat.com MIME-Version: 1.0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: 7bit On 10/03/2012 12:44 PM, David Teigland wrote: > You might be able to assign > different numbers of votes to reduce the likelihood of everyone loosing > quorum. > (Late to thread - here's an example of what David is talking about): Node Votes ----- ----- node1 1 node2 2 node3 3 node4 5 Total: 11 Quorate 2-node partition: - node1 node4 (6 votes / 11) - node2 node4 (7 / 11) - node3 node4 (8 / 11) Inquore 2-node partition: - node1 node2 (3 / 11) - node1 node3 (4 / 11) - node2 node3 (5 / 11) Effectively, no matter how a 2:2 partition occurs in this configuration, one partition will always have quorum (and thus be able to fence). Like a normal 4-node cluster, one node can always fail while the other 3 nodes remain quorate. -- Lon