[PATCH 1/3] common: Factor out function to get OS name

Jan Kara
2015-11-24T10:40:04Z

Signed-off-by: Jan Kara <jack@suse.cz>
---
common/rc | 22 ++++++++++++++--------
1 file changed, 14 insertions(+), 8 deletions(-)

diff --git a/common/rc b/common/rc
index 4c2f42c8d0eb..81418280f163 100644
--- a/common/rc
+++ b/common/rc
@@ -2188,6 +2188,18 @@ _full_platform_details()
echo "$os/$platform $host $kernel"
}

+_get_os_name()
+{
+ if [ "`uname`" == "IRIX64" ] || [ "`uname`" == "IRIX" ]; then
+ echo 'irix'
+ elif [ "`uname`" == "Linux" ]; then
+ echo 'linux'
+ else
+ echo Unknown operating system: `uname`
+ exit
+ fi
+}
+
_link_out_file()
{
if [ -z "$1" -o -z "$2" ]; then
@@ -2195,14 +2207,8 @@ _link_out_file()
exit
fi
rm -f $2
- if [ "`uname`" == "IRIX64" ] || [ "`uname`" == "IRIX" ]; then
- ln -s $1.irix $2
- elif [ "`uname`" == "Linux" ]; then
- ln -s $1.linux $2
- else
- echo Error test $seq does not run on the operating system: `uname`
- exit
- fi
+ SUFFIX=$(_get_os_name())
+ ln -s $1.$SUFFIX $2
}

_die()
--
2.1.4