[PATCH 2/2] Ensure git ls-tree exits with a non-zero exit code if read_tree_recursive fails.

[Jon Seymour <jon.seymour@gmail.com>]

In the case of a corrupt repository, git ls-tree may report an error but
presently it exits with a code of 0.

This change uses the return code of read_tree_recursive instead.

Signed-off-by: Jon Seymour <jon.seymour@gmail.com>
---
 builtin/ls-tree.c |    6 +++---
 1 files changed, 3 insertions(+), 3 deletions(-)

diff --git a/builtin/ls-tree.c b/builtin/ls-tree.c
index f08c5b0..6d6c992 100644
--- a/builtin/ls-tree.c
+++ b/builtin/ls-tree.c
@@ -120,7 +120,7 @@ int cmd_ls_tree(int argc, const char **argv, const char *prefix)
 {
 	unsigned char sha1[20];
 	struct tree *tree;
-	int i, full_tree = 0;
+	int i, full_tree = 0, err;
 	const struct option ls_tree_options[] = {
 		OPT_BIT('d', NULL, &ls_options, "only show trees",
 			LS_TREE_ONLY),
@@ -173,7 +173,7 @@ int cmd_ls_tree(int argc, const char **argv, const char *prefix)
 	tree = parse_tree_indirect(sha1);
 	if (!tree)
 		die("not a tree object");
-	read_tree_recursive(tree, "", 0, 0, &pathspec, show_tree, NULL);
+	err = read_tree_recursive(tree, "", 0, 0, &pathspec, show_tree, NULL);
 
-	return 0;
+	return err;
 }
-- 
1.7.6.347.g6a5a9c